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See Plans →Simple interest is calculated using the formula:
\(I = \dfrac{P \times R \times T}{100}\)
where P = Principal (the amount invested or borrowed), R = Rate (the annual interest rate as a percentage), and T = Time (in years).
With simple interest, the same amount of interest is earned every year — it is always calculated on the original principal, not on the growing total.
Find the simple interest on £500 invested at 3% per year for 4 years.
P = £500, R = 3, T = 4
\(I = \dfrac{500 \times 3 \times 4}{100} = \dfrac{6000}{100} = \) £60
Total = £500 + £60 = £560
Calculate the simple interest on £1,200 at 4.5% per year for 2 years.
P = £1,200, R = 4.5, T = 2
\(I = \dfrac{1200 \times 4.5 \times 2}{100} = \dfrac{10800}{100} = \) £108
Calculate the simple interest on £900 at 6% per year for 8 months.
T must be in years: \(8 \text{ months} = \dfrac{8}{12} = 0.6\overline{6}\) years (keep the full decimal, don't round yet)
P = £900, R = 6, T = 8/12: \(I = \dfrac{900 \times 6 \times \frac{8}{12}}{100} = \dfrac{3600}{100} = \) £36
Once you have calculated the interest \(I\), you can find the total amount (sometimes called the final amount or amount due) by adding the interest to the principal:
\(\text{Total Amount} = P + I\)
This can also be written as \(A = P + \dfrac{PRT}{100}\), or more compactly as \(A = P\!\left(1 + \dfrac{RT}{100}\right)\).
Find the total amount when £1,000 is invested at 5% simple interest per year for 3 years.
\(I = \dfrac{1000 \times 5 \times 3}{100} = \dfrac{15000}{100} = \) £150
Total = £1,000 + £150 = £1,150
You invest £800 in a savings account paying 2.5% simple interest per year for 5 years. What is the total amount in the account at the end?
\(I = \dfrac{800 \times 2.5 \times 5}{100} = \dfrac{10000}{100} = \) £100
Total = £800 + £100 = £900
The formula \(I = \dfrac{PRT}{100}\) can be rearranged to find any one of the four variables if the other three are known:
In each case, multiply \(I\) by 100, then divide by the product of the other two variables.
£500 was invested for 3 years and earned £75 in simple interest. Find the annual rate of interest.
P = £500, T = 3, I = £75, R = ?
\(R = \dfrac{100 \times I}{P \times T} = \dfrac{100 \times 75}{500 \times 3} = \dfrac{7500}{1500} = \) 5%
£800 is invested at 4% simple interest per year. It earns £128 in interest. For how many years was it invested?
P = £800, R = 4, I = £128, T = ?
\(T = \dfrac{100 \times I}{P \times R} = \dfrac{100 \times 128}{800 \times 4} = \dfrac{12800}{3200} = \) 4 years
An investment at 5% per year for 3 years earned £90 in simple interest. How much was originally invested?
R = 5, T = 3, I = £90, P = ?
\(P = \dfrac{100 \times I}{R \times T} = \dfrac{100 \times 90}{5 \times 3} = \dfrac{9000}{15} = \) £600
Use \(I = PRT \div 100\) to calculate the interest for each row. Type your answer in pounds, then click Check.
| # | Question | Answer | Result |
|---|---|---|---|
| 1 | £500 at 3% for 2 years | ||
| 2 | £1,000 at 5% for 3 years | ||
| 3 | £2,000 at 2% for 4 years | ||
| 4 | £750 at 4% for 1 year | ||
| 5 | £600 at 6% for 5 years | ||
| 6 | £900 at 4% for 2 years | ||
| 7 | £1,500 at 3% for 2 years | ||
| 8 | £300 at 5% for 3 years | ||
| 9 | £2,500 at 2% for 1 year | ||
| 10 | £1,200 at 6% for 2 years |