Functional Skills Level 2 — Shape: Perimeter and Area

Composite Area

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Strategy for Composite Areas

Composite (compound) shapes are made of two or more simple shapes joined together — or a simple shape with a piece cut out. There are two key approaches:

Method 1: ADD

Split the shape into simpler parts.
Find each area separately.
Add them together.

A = A₁ + A₂
Method 2: SUBTRACT

Find the area of a large simple shape.
Subtract the cut-out piece.
Result = remaining area.

A = Abig − Acut
💡 Tip: Both methods work for L-shapes. Choose whichever feels easier. Always label the parts clearly and show your working.
✓ Quick Check 1 — Strategy for Composite Areas
Question 1 of 10
L-Shape Decomposition

An L-shape that is 10 cm wide and 8 cm tall, with a 4 cm × 3 cm notch cut from the top-right corner.

Method A: Add two rectangles 10 × 5 = 50 6 × 3 = 18 width = 10 cm h = 5 50 + 18 = 68 cm² Method B: Big rectangle minus notch 4×3 cut 10 × 8 = 80 80 − 12 = 68 cm² OR
📄 Worked: L-shape (subtract method)
Step 1 — Big rectangle
10 × 8 = 80 cm²
Step 2 — Notch cut out
4 × 3 = 12 cm²
Step 3 — Subtract
80 − 12 = 68 cm²
T-Shape

A T-shape split into a horizontal top bar and a vertical stem. The two colours show the two rectangles.

12 cm 2 cm 8 cm 4 cm 12 × 2 = 24 4 × 8 = 32 Total area: 24 + 32 = 56 cm²
📄 Worked: T-shape
Step 1 — Top bar
12 × 2 = 24 cm²
Step 2 — Vertical stem
4 × 8 = 32 cm²
Step 3 — Total
24 + 32 = 56 cm²
✓ Quick Check 2 — L-Shapes and Rectilinear Shapes
Question 1 of 10
Rectangle with a Semicircle

A rectangle (10 cm × 6 cm) with a semicircle of diameter 6 cm attached to one end (radius = 3 cm).

10 cm 6 cm r=3 10 × 6 = 60 A = 60 + (π × 3² ÷ 2) = 60 + 14.14 Total = 74.14 cm²
📄 Worked: Rectangle + Semicircle
Step 1 — Rectangle
A = 10 × 6 = 60 cm²
Step 2 — Semicircle (radius = 3 cm)
A = π × r² ÷ 2 = π × 9 ÷ 2 = 14.14 cm²
Step 3 — Total
60 + 14.14 = 74.14 cm²
Note
This uses full-precision π. If a question tells you to use π ≈ 3.14 instead, you'll get 74.13 cm² — a 0.01 cm² difference from rounding, not a mistake.
💡 Semicircle formula: A = ½ × π × r². Always halve the full circle area. Make sure you use the radius, not the diameter.
✓ Quick Check 3 — Rectangle + Semicircle Composites
Question 1 of 10
Annulus (Ring Shape)

An annulus is a large circle with a smaller circle removed from the centre — like a ring or a washer. Subtract the inner circle area from the outer circle area.

R = 8 cm r=3 hole π×8² − π×3² = 201.06 − 28.27 = 172.79 cm²
📄 Worked: Annulus (R = 8 cm, r = 3 cm)
Step 1 — Outer circle
A = π × 8² = π × 64 = 201.06 cm²
Step 2 — Inner circle (hole)
A = π × 3² = π × 9 = 28.27 cm²
Step 3 — Subtract
201.06 − 28.27 = 172.79 cm²
Annulus area = π × R² − π × r² = π(R² − r²)
✓ Quick Check 4 — Shapes with Semicircles and Cut-Outs
Question 1 of 10
✓ Quick Check 5 — Multi-Step Real Life Problems
Question 1 of 10

Practice: Extra Questions

Work out each answer, then type it in and click Check to see if you're right.

# Question Your answer Result
1 An L-shape is made from a 8 cm × 6 cm rectangle with a 3 cm × 2 cm rectangle removed from one corner. What is the area?
2 A shape is formed by joining a 10 cm × 4 cm rectangle and a 5 cm × 3 cm rectangle. What is the total area?
3 A 12 cm × 8 cm rectangle has a 4 cm × 4 cm square cut from one corner. What is the remaining area?
4 A T-shape: a 10 cm × 2 cm strip sits on top of a 6 cm × 4 cm rectangle. What is the total area?
5 Two rectangles: 7 cm × 5 cm and 3 cm × 5 cm placed side by side. What is the total area?
6 An L-shape: split into a 9 cm × 3 cm rectangle and a 4 cm × 6 cm rectangle. What is the total area?
7 L-shape: rectangle 8 cm × 3 cm plus rectangle 4 cm × 5 cm. What is the total area?
8 A 10 cm × 6 cm rectangle has a 3 cm × 2 cm piece cut from a corner. What is the remaining area?
9 A rectangle 6 cm × 4 cm has a triangle (base 6 cm, height 3 cm) sitting on top. What is the total area?
10 A rectangle 10 cm × 6 cm has a semicircle (r = 3 cm) attached to one side. Use π = 3.14. What is the total area to 2 d.p.?
11 A square 8 cm × 8 cm has a circle (r = 2 cm) cut from the middle. Use π = 3.14. What is the remaining area to 2 d.p.?

⚠ Things to Watch Out For

  • Make sure you split the composite shape into recognised sub-shapes correctly — an incorrect split leads to wrong areas.
  • If a sub-shape is cut out (subtracted), subtract its area — don't add it again by mistake.
  • Identify the correct dimensions for each sub-shape; some measurements may need to be calculated from the overall dimensions first.
  • Don't double-count a shared boundary — it is an edge of one shape only, not two.
  • Give your final area in square units throughout (cm², m², etc.).
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